有限数学示例

$C = 100 x + 200$ , $R = 120 x$

解题步骤 1

Move variables to the left and constant terms to the right.

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解题步骤 1.1

从等式两边同时减去 $100 x$ 。

$C - 100 x = 200$

$R = 120 x$

解题步骤 1.2

从等式两边同时减去 $120 x$ 。

$C - 100 x = 200$

$R - 120 x = 0$

$C - 100 x = 200$

$R - 120 x = 0$

解题步骤 2

Write the system as a matrix.

$[\begin{array}{c} 1 & 0 & - 100 & 200 \\ 0 & 1 & - 120 & 0 \end{array}]$

解题步骤 3

Use the result matrix to declare the final solution to the system of equations.

$C - 100 x = 200$

$R - 120 x = 0$

解题步骤 4

The solution is the set of ordered pairs that make the system true.

$(200 + 100 x, 120 x, x)$

有限数学 示例